=∫[(2^x)?2·2^x·3^x +(3^x)瞉dx
=∫(4^x +2·6^x +9^x)dx
=∫4^xdx+2∫6^xdx+∫9^xdx
=(1/ln4)4^x +(2/ln6)6^x +(1/ln9)9^x +C
匿名回答于2024-05-14 17:02:46
