a的平方加2a等于2怎么算？

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

a^2+2a+2

=a^2+2a+1+1

=(a+1)^2+1

匿名回答于2024-05-13 15:19:34

a的平方加2a等于2列方程得a²+2a＝2，这个一元二次方程的解是a1=－1+根号3，a2=－1－根号3。在方程两边都加上1得，a²+2a+1=2+1=3，配方后得到，（a+1）²=3，两边开平方得，a+1=±根号3，移项得，a=－1±根号3，所以这个一元二次方程的解是a1=－1+根号3，a2=－1－根号3。

匿名回答于2024-04-25 15:55:05