令z=(1-2x)/(1-x-y),则z=(1-2ln3/ln12)/(1-ln3/ln12-ln2/ln12)=(ln12-ln9)/(ln12-ln3-ln2)=(ln4/ln3)/ln2=(ln4-ln3)/ln2=2-ln3/ln2=2-log(3/2)于是12^((1-2x)/(1-x-y))=12^(2-log(3/2))=12^2/12^(log(3/2))=144/(2^(log(3/2))2^(log(3/2))3^(log(3/2)))=144/3×3×(1/2)=32。
匿名回答于2024-05-14 17:01:02
匿名回答于2024-05-04 05:53:34